WADA said it reminds the cycling body that the agency “which

discovered the violation must have results management authority” in a

case. Armstrong could lose his seven Tour de France titles if he is

found to have doped throughout his career, as USADA alleges. WADA says

there is “no provision” within its rules “that allows the UCI to

interfere with the USADA case” or demand to see the American agency’s

evidence. The three sports groups have engaged in a testy exchange in

recent days just as Armstrong prepares for a federal court hearing in

Austin, Texas, where he will ask U.S. District Judge Sam Sparks to

block USADA from pursuing its case.nike air max shoes He argues that UCI has proper

jurisdiction. In a statement released last week, UCI complained that

USADA has refused to share its evidence — not only with Armstrong but

with the UCI itself. USADA chief executive Travis Tygart responded by

saying UCI has an interest in covering up corruption in cycling and

alleged performance-enhancing drug use by Armstrong and members of his

teams. USADA has accused Armstrong of performance-enhancing drug use

throughout his career, from his Tour de France victories from 1999-2005

through his comeback a few years ago. Armstrong vehemently denies the

charges and says the USADA arbitration process is unfair. The cyclist

also points to a clean record throughout his career when it comes to

drug testing. An Armstrong spokesman declined comment Tuesday.

Armstrong’s attorneys have raised the UCI jurisdiction claims in their

court filings. They say that blood and urine samples cited in USADA’s

allegations belong to UCI and that emails from former Armstrong

teammate Floyd Landis outlining alleged doping on Armstrong’s teams

were first sent to a USA Cycling official, who falls under UCI’s

jurisdiction. Armstrong’s attorneys say now that UCI has asserted its

jurisdiction, USADA’s case must stop. Copyright 2012 The Associated

Press. All rights reserved. This material may not be published,

broadcast, rewritten or redistributed.

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